(x^2-7x+11)^x^2-13x+42=1

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Solution for (x^2-7x+11)^x^2-13x+42=1 equation: 



(x^2-7x+11)^x^2-13x+42=1

We move all terms to the left:

(x^2-7x+11)^x^2-13x+42-(1)=0

We add all the numbers together, and all the variables

-13x+(x^2-7x+11)^x^2+41=0

We move all terms containing x to the left, all other terms to the right

-13x+(x^2-7x+11)^x^2=-41

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